How Famous Is Jane Krakowski?
Actor
TV Personality
Musician
According to our voters, Jane Krakowski is the...
864th most famous person in the world!
Fame by country
Most famous in United States
Jane Krakowski is an acclaimed American actress known for her roles in TV series like '30 Rock' and 'Ally McBeal.' She has also had a successful career on Broadway, winning a Tony Award.
Wins
27
Losses
54
ELO
1507
Most recently Jane Krakowski lost a matchup to Sofia Coppola (#389) voted by someone from Netherlands.
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Recent head-to-head battles
Per-country vote breakdown
| Country | Rank | Win Rate |
|---|---|---|
| πΊπΈ United States | #93 | 51.7% |
| π¨π¦ Canada | #574 | 63.6% |
| π«π· France | #611 | 0.0% |
| π¬π§ United Kingdom | #1145 | 25.0% |
| πΈπ¬ Singapore | #1608 | 16.7% |
| π©πͺ Germany | #1661 | 25.0% |
| π§πͺ Belgium | #1874 | 0.0% |
| π³π± Netherlands | #2121 | 0.0% |
| π¦πΉ Austria | #2141 | 0.0% |
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